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<!doctype html>
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<meta charset="utf-8" />
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<title>
Winform 应用程序 Image OOM 异常的处理方法 - MayGodBlessYou
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<h1>Winform 应用程序 Image OOM 异常的处理方法</h1>
<div class="read-more clearfix">
<span class="date">2014/08/18</span>
<span>posted in </span>
<span class="posted-in"><a href='dotNET.html'>dotNET</a></span>
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<p>在做Winform应用程序处理Image时碰到了这样一个问题。</p>
<span id="more"></span><!-- more -->
<p>窗体设计如下：</p>
<p><img src="https://objectstorage.ap-tokyo-1.oraclecloud.com/n/nrql75upzuqs/b/bucket-liberty-blog-20240513/o/jackro_blog2014081801.jpg" alt="jackro_blog2014081801" /></p>
<p>当点击上面窗体中的上一张和下一张时，PictureBox中的图片会跟着切换，但是切换时却抛出了如下图所示的异常：</p>
<p><img src="https://objectstorage.ap-tokyo-1.oraclecloud.com/n/nrql75upzuqs/b/bucket-liberty-blog-20240513/o/jackro_blog2014081802.jpg" alt="jackro_blog2014081802" /></p>
<p>内存不足！！！<br />
我一开始的关键代码如下所示：</p>
<pre><code class="language-plain_text"> private void Form1_Load(object sender, EventArgs e)
{
pictureBox1.Image = Image.FromFile(@"f:\图片\1.jpg");
}
string[] path = Directory.GetFiles(@"f:\图片");
int i = 0;
private void button2_Click(object sender, EventArgs e)
{
i++;
if (i == path.Length)
{
i = 0;
}
pictureBox1.Image = Image.FromFile(path[i]);
}
private void button1_Click(object sender, EventArgs e)
{
i--;
if (i < 0)
{
i = path.Length - 1;
}
pictureBox1.Image = Image.FromFile(path[i]);
}
</code></pre>
<p>后来，我在博客园里找问题的答案，找到了如下几种解决办法：</p>
<p><strong><1>释放内存</strong></p>
<p>每次在PictureBox中显示完图像时，将其释放掉。释放内存关键代码如下：</p>
<pre><code class="language-plain_text"> //if (pictureBox1.Image != null)//
{// pictureBox1.Image.Dispose();//}
//或者像下面这样回收所有资源// GC.Collect();
</code></pre>
<p><strong><2>双缓冲(类似于GDI+中的双倍缓冲)</strong><br />
就是创建一个缓冲的“内存库”来存储图像，关键代码如下：</p>
<pre><code class="language-plain_text"> //Bitmap bmp = new Bitmap(path[i]); //bmp即相当于一个缓冲的“内存库”
//pictureBox1.Image = (Image)bmp;
</code></pre>
<p><strong><3>自己琢磨出来的解决方法</strong><br />
这种方法也可以释放内存，释放内存通过bmp和Image的Dispose()方法实现。<br />
上面两种方法我都试了，可是都还是会抛出异常。后来我经过多次的调试，找到了一种解决问题的办法，这种办法我觉得很奇怪，有点匪夷所思。我先把解决问题的代码展示出来供诸君参考吧，希望看到的大猿能帮我解释下其中的道理。<br />
我只改了我自己写的代码中的“遍历”的范围，修改的关键部分如下所示：</p>
<pre><code class="language-plain_text"> private void button2_Click(object sender, EventArgs e)
{
i++;
if (i == path.Length - 1)
{
i = 0;
}
pictureBox1.Image = Image.FromFile(path[i]);
}
private void button1_Click(object sender, EventArgs e)
{
i--;
if (i < 0)
{
i = path.Length - 2;
}
pictureBox1.Image = Image.FromFile(path[i]);
GC.Collect();
}
</code></pre>
<p>这种方法既没有释放内存，也没有做缓冲的“内存库”存图像，可是程序却跑的很正常，实在让人费解其中的道理。希望看到的大猿能给我解释下这其中的道理，感激不尽！</p>
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