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Why use the sign function in the cos(m*the) #1

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Erdos001 opened this issue Jan 16, 2018 · 3 comments

Erdos001 commented Jan 16, 2018

cos_sign = tf.sign(cos_th)

res = 2*tf.multiply(tf.sign(cos_th), tf.square(cos_th)) - 1

what's the mean of the sign function in calculate the cos(m*th)

Author

Erdos001 commented Jan 16, 2018

Sorry， I see. For th reason that demonstrated in the paper

yinghuang commented Jul 11, 2018

@Erdos001 so what's the meaning? where should I look in the paper?

wangyongjie-ntu commented Dec 19, 2018

@Erdos001 can you point why the author add sign function?

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