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alternative and easy method for question 1 #139

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ghost opened this issue Jan 17, 2021 · 3 comments
Open

alternative and easy method for question 1 #139

ghost opened this issue Jan 17, 2021 · 3 comments

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@ghost
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ghost commented Jan 17, 2021

hi. I just want to make the code for question 1 much simpler and easily understandable for beginners

for i in range(2000, 3201):
    if (i%7==0) and (i%5!=0):
      print(i,end=",")

cool?

@RohanSardar
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yes, your one is easier to understand

@Varun270
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Hi, I am a newbie to open source can anyone tell me whether this issue is fixed or not.

@RohanSardar
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Hi, I am a newbie to open source can anyone tell me whether this issue is fixed or not.

according to me, it's fixed

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